Chemistry Peas Urgent Help Needed ASAP (Final Today)

Oh dear, my senior chemistry major is at work. Let me see if I can text her.

She is looking at it now for you.

I'm not positive what you're asking, but that reaction that is written as the answer for (C) can go either direction - the ions break apart to form the equation on the right, or they are bound together to form the one on the left. They'd combine in ways that balance out the cations and anions - positive binds with negative to neutralize the charge.

The pH question in (G) is more complicated - the pH of a solution is a known and then you account for water I believe, and I'm going to suggest for that one reading over the Q&A on the chemistry help boards, since it will involve logs and molarity.

If she's right up against the final exam time, I'd skip the second one and focus on the first.

Maybe someone else can explain the pH question quickly, I can't seem to do it with out drawing diagrams and using my hands. Also I need more coffee. I hope she does well.

ETA I see Patter is going to hook you up with a chemist - yay! - and here's the link I mentioned about pH concentration: chemistry.stackexchange.com/questions/44150/how-to-calculate-the-concentration-h3o-in-a-solution-with-ph-6-99

Oh man, she typed up a long e-mail, and it's lost in cyberspace and she is now in a meeting. She will resend in a bit. I am SO sorry. How many hours until her exam? I will post as soon as she gets it to me again. Man, I hate the internet sometimes.

Okay, here you go. I pray it helps her in some way! And sorry if there are typos. She was typing fast and trying to get back to work.

8c: When molecules react, they separate and reform according got cations and anions. In reactants side of the equation you have CaCO3 which disassociates into Ca 2+ and CO32- is the carbonate anion it will never disassociate unto the individual atoms, then you have H2O which readily dissociates into H and OH-. Now, you need to think of how these cations and anions would go together, OH- is stable on its own most of the time, so you do not need to add a cation to it. The most important thing to look at it balancing the charge. Ca2+ is also stable in the equation so we can leave it be, bicarbonate, (HCO3-) readily forms with water. Next, you check to be sure the carges balance on both sides. This problem is mainly knowing what cations and anions are stable and which ones will form more readily than others.

8g: You know from the previous problem that the pH is 11.71; therefore, the definition of pH is the concentration of H+ in the solution. Using this information and the pH equation gives the formula [H+] = 10-ph; therefore, solving this equation gives the concentration of H+ in the solution.