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Post by *Shannon on Jun 10, 2016 2:09:26 GMT
Hello math wizards - My daughter is completing some school work. She's not sure she's doing this correctly. She said that videos she watched didn't really help her understand it any better. Can someone tell me if she completed #3 & #4 (posted out of order) correctly? I have not a single clue. I am not smarter than a 9th grade (in math). Thank you!
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Post by mlynn on Jun 10, 2016 2:14:06 GMT
I cannot read her answers
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Post by mom on Jun 10, 2016 2:17:15 GMT
#3 is wrong. The 3 should distribute to the y and the x.
It should be y3x9 * - x5y2
I cant read her answer for #4
edited to add the *times* sign that I left off the first time.
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Post by gale w on Jun 10, 2016 2:23:22 GMT
#3 is wrong. The 3 should distribute to the y and the x. It should be y 3x 9 - x 5y 2I cant read her answer for #4 It's hard to see it but there is a * in there (it's a dot on the page). So it's y 3x 9 * -x 5y 2At least I think there is. It's not easy to read.
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Post by mom on Jun 10, 2016 2:25:32 GMT
#3 is wrong. The 3 should distribute to the y and the x. It should be y 3x 9 - x 5y 2I cant read her answer for #4 It's hard to see it but there is a * in there (it's a dot on the page). So it's y 3x 9 * -x 5y 2At least I think there is. It's not easy to read. You are absolutely right. LOL
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Post by *Shannon on Jun 10, 2016 2:29:05 GMT
Thank you so much, ladies. I'll get the sheet and write her answer down. Sorry about that.
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Post by *Shannon on Jun 10, 2016 2:32:59 GMT
Ok, she said she knows its wrong... so would either of you be willing to work the problem (#4) so I can show her the answer? Thank you!
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Post by freecharlie on Jun 10, 2016 2:33:18 GMT
#4 is wrong based on the instruction to ensure all exponents are positive. (I didn't check the math)
in order to make a negative exponent postive, you would move it to the denomenator.
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MsKnit
Pearl Clutcher
RefuPea #1406
Posts: 2,648
Jun 26, 2014 19:06:42 GMT
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Post by MsKnit on Jun 10, 2016 2:35:04 GMT
Where are the problems?
Sorry. Took forever for them to show up.
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Post by freecharlie on Jun 10, 2016 2:36:12 GMT
They are images embedded in her post
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Post by giraffemom on Jun 10, 2016 3:00:58 GMT
Purplemath.com has a great way to explain stuff like this. Good luck! carol
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MsKnit
Pearl Clutcher
RefuPea #1406
Posts: 2,648
Jun 26, 2014 19:06:42 GMT
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Post by MsKnit on Jun 10, 2016 3:14:25 GMT
I can't get a pic to upload. When multiplying a value with an exponent with another of that same value with an exponent. The exponents are added. So x to the exponent of 3 times x to the exponent of 2 equals x to the exponent of 5. When multipying an exponent to an exponent, the exponents are multiplied. For #4 you have: -x -2y 2 times (x -1y 2) -4-x -2y 2 times x 4y -8(-1)(x -2)(y 2)(x 4)(y -8)----This is what you have when each value is broken down. Ans: -x 2y -6She can also put the values in their proper place on a division problem, as such y 2 x 4 - __________ x ___________ , then work the problem. x 2 y 8 A negative exponent is on the opposite side of the divisor line, which is why these were placed in the denominator. There is more than one way to work a problem. Sometimes it's easier to break it down into a simpler form. Don't laugh. Edited because it smooshed info to the left.
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Post by pepperwood on Jun 10, 2016 3:14:52 GMT
It's hard to see it but there is a * in there (it's a dot on the page). So it's y 3x 9 * -x 5y 2At least I think there is. It's not easy to read. You are absolutely right. LOL In #3:
y3x9 * -x5y2 can be further simplified by grouping the x and Y terms as follows:
x9 * -x5 * y3*y2 *which then becomes -x(9+5) *y(3+2) = -x(14)y5
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MsKnit
Pearl Clutcher
RefuPea #1406
Posts: 2,648
Jun 26, 2014 19:06:42 GMT
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Post by MsKnit on Jun 10, 2016 3:19:52 GMT
You are absolutely right. LOL y3x9 * -x5y2 can be further simplified by grouping the x and Y terms as follows:
x9 * -x5 * y3*y2 *which then becomes -x(9+5) *y(3+2) = -x(14)y5
Also, something that can be helpful...the negative in front of the x^5 implies a negative one. I've found thinking in this term regarding the negative is helpful to the students I tutor. It helps to keep that negative from accidentally being forgotten.
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MsKnit
Pearl Clutcher
RefuPea #1406
Posts: 2,648
Jun 26, 2014 19:06:42 GMT
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Post by MsKnit on Jun 10, 2016 3:24:44 GMT
You are absolutely right. LOL In #3:
y3x9 * -x5y2 can be further simplified by grouping the x and Y terms as follows:
x9 * -x5 * y3*y2 *which then becomes -x(9+5) *y(3+2) = -x(14)y5
How did you get the exponent in the proper position?
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Post by pepperwood on Jun 10, 2016 3:36:40 GMT
y3x9 * -x5y2 can be further simplified by grouping the x and Y terms as follows:
x9 * -x5 * y3*y2 *which then becomes -x(9+5) *y(3+2) = -x(14)y5
How did you get the exponent in the proper position?
I am embarrassed to admit that it was more challenging to figure out how to type the exponent. If you use the quote option to reply, if you click the 6th icon at the top is the letter A with a superscript the text that you type next will be in the proper position. After you finish typing the exponent, hit the icon again to return to regular type.
I learned the hard way that there is no superscript icon when you type in your reply at the bottom of the thread.
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Post by *Shannon on Jun 10, 2016 3:37:10 GMT
Thank you all so much! I will show my daughter your explanations, MsKnit and pepperwood. Thank you for the website suggestions mom and giraffemom.
THANK YOU!!!!
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MsKnit
Pearl Clutcher
RefuPea #1406
Posts: 2,648
Jun 26, 2014 19:06:42 GMT
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Post by MsKnit on Jun 10, 2016 4:21:00 GMT
How did you get the exponent in the proper position?
I am embarrassed to admit that it was more challenging to figure out how to type the exponent. If you use the quote option to reply, if you click the 6th icon at the top is the letter A with a superscript the text that you type next will be in the proper position. After you finish typing the exponent, hit the icon again to return to regular type.
I learned the hard way that there is no superscript icon when you type in your reply at the bottom of the thread.
x 2 How about that? LOL! Thank you!
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